Back To C++ Menu Driven Programs

//menu driven program to find area of triangle,circle,square and rectangle using do-while and switch statement  (example of menu driven program)
#include<iostream.h>
#include<conio.h>
#include<math.h>
void triangle(int side1,int side2,int side3)
{
	float area,s;
	s=(side1+side2+side3)/2;
	area=sqrt(s*(s-side1)*(s-side2)*(s-side3));
	cout<<"\narea of triangle is "<<area;
}
void circle(int radius)
{
	float area;
	area=3.14*radius*radius;
	cout<<"\narea of circle is "<<area;
}
void square(int side)
{
	float area;
	area=side*side;
	cout<<"\narea of square is "<<area;
}
void rectangle(int length,int breadth)
{
	float area;
	area=length*breadth;
	cout<<"\narea of rectangle is "<<area;
}
void main()
{

int side1,side2,side3,side,length,breadth,radius;
	int choice;
	char ch;
	do
	{
        clrscr();
	cout<<"\nMenu to Find Area     ";
	cout<<"\n1. Triangle ";
	cout<<"\n2. Circle ";
	cout<<"\n3. Square ";
	cout<<"\n4. Rectangle ";
	cout<<"\nEnter your choice (1,2,3,4) ";
	cin>>choice;
	switch(choice)
	{
		case 1: cout<<"\nenter side 1 of triangle ";
				cin>>side1;
				cout<<"\nenter side 2 of triangle ";
				cin>>side2;
				cout<<"\nenter side 3 of triangle ";
				cin>>side3;
				triangle(side1,side2,side3);
				break;
		case 2: cout<<"\nEnter radius of circle ";
				cin>>radius;
				circle(radius);
				break;
		case 3: cout<<"\nEnter side of square ";
				cin>>side;
				square(side);
				break;
		case 4: cout<<"\nenter length of rectangle ";
				cin>>length;
				cout<<"\nenter breadth of rectangle ";
				cin>>breadth;
				rectangle(length,breadth);
				break;
		default:cout<<"enter a valid choice (1,2,3,4)";
	}
	cout<<"\ndo you want to continue (y/n)";
	cin>>ch;
	}while((ch=='y') || (ch=='Y'));
	getch();
}